2023年6月21日发(作者:)
SQL练习题库
表结构
Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表
试题:
1、查询“0001”课程比“C002”课程成绩高的所有学生的学号;
Select s# from sc
Where c#='0001' and score>any(select score from sc c#='0002')
2、查询平均成绩大于60分的同学的学号和平均成绩;
select s#,avg(score) from SC
group by s#
having avg(score)>60
3、查询所有同学的学号、姓名、选课数、总成绩;
select student.s#,,count(sc.c#)as 选课数,sum(score)总成绩 from student,sc
where student.s#=sc.s#
group by student.s#,
4、查询姓“张”的老师的个数;
select count(*)人数 from teacher
where tname like'张%'
5、查询没学过“叶平”老师课的同学的学号、姓名;
select student.s#, from student,course,teacher,sc
where student.s#=sc.s# and course.t#=teacher.t# and teacher.t# not in(select t# from teacher where tname='张丽芬')
group by student.s#,
6、查询学过“0001”并且也学过编号“0002”课程的同学的学号、姓名;
select sc.s#,sname from sc,student
where sc.c# = '0001' and student.s# = sc.s# and sc.s# in (select s# from sc where sc.c# = '0002')
--并(两表值)
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0001'
union
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0002'
--交(有相同值)
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0001'
intersect
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0002'
--差(不同值)
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0001'
except
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0002'
7、查询学过“叶平”老师所教的所有课的同学的学号、姓名; select student.s#, from student,course,teacher,sc
where student.s#=sc.s# and course.t#=teacher.t# and teacher.t# in(select t# from teacher where tname='张丽芬')
group by student.s#,
8、查询课程编号“001”的成绩比课程编号“002”课程低的所有同学的学号、姓名;
select student.s#,sname,score from student,sc
where student.s#=sc.s# and score in(( select score from sc where c#='0001' ) 9、查询所有课程成绩小于60分的同学的学号、姓名; select student.s#,sname from student where s# in( select s# from sc where score<60) 10、查询没有学全所有课的同学的学号、姓名; select student.s#, from student,sc where student.s#=sc.s# group by student.s#, having count(c#)<(select count(c#) from course) 11、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名; select student.s#, from student,sc where student.s#=sc.s# and c#=any( select c# from sc where s#='1001' ) group by student.s#, 12、查询至少学过学号为“0001”同学所有一门课的其他同学学号和姓名; Select sc.s#,sname from sc inner join student on sc.s#=student.s# Where c# in (select c# from sc where s#=’0001’) 13、把“SC”表中“赵雁南”老师教的课的成绩都更改为此课程的平均成绩; update sc set score=(select avg() from sc,teacher,course where sc.c#=course.c# and course.t#=teacher.t# and ='赵雁南') where sc.c#=(select c# from course,teacher where course.t#=teacher.t# and tname='赵雁南' ) 14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名; select student.s#,sname from student,sc where student.s#=sc.s# and sc.c#=all(select c# from sc where s#='1005') and student.s#<>'1005' 15、删除学习“朱玉文”老师课的SC表记录; delete from sc where c# in(select c# from sc where c# in (select c# from course,teacher where teacher.t#=course.t# and ='朱玉文' ) ) 16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“0002”课程的同学学号、号课的平均成绩; insert into sc values select s# from sc where s# not in (select s# from sc where c#='0002' select avg(score) as 平均成绩 from sc where c#='0002' 17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示:学生ID,,数据库,企业管理,英语,有效课程数,有效平均分 select sc.s#,,,avg(score)as 平均成绩 from sc inner join course on sc.c#=course.c# where sc.c# in(select c# from course where cname=any(select cname from course where cname in('计算机基础','Oracle','软件工程'))) group by sc.s#,, order by avg(score) desc SELECT S# as 学生ID ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='0001') AS 计算机基础 ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='0002') AS Oracle ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='0011') AS 软件工程 ,COUNT(*) AS 有效课程数, AVG() AS 平均成绩 FROM sc AS t GROUP BY S# ORDER BY avg() desc 18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分 select c# 课程ID,max(score) 最高分,min(score) 最低分 from sc group by c# 19、按各科平均成绩从低到高和及格率的百分数从高到低顺序 select c#, avg(score) from sc where score>60 group by c# 20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(),马克思(),OO&UML 21、查询不同老师所教不同课程平均分从高到低显示 select course.t#,avg() as 平均分 from sc,course where sc.c#=course.c# group by course.t# order by avg() desc 22、查询如下课程成绩第3 名到第6 名的学生成绩单:企业管理,马克思,UML,数据库 [学生ID],[学生姓名],企业管理,马克思,UML,数据库,平均成绩 select student.s#,,, from student inner join sc on student.s#=sc.s# inner join course on sc.c#=course.c# where in('oracle','电路分析','计算机基础') order by , desc 23、统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60] select sc.c#,,count(*)人数 from sc,course where course.c#=sc.c# group by sc.c#, 24、查询学生平均成绩及其名次 select sc.s#,avg(score) from sc group by sc.s# order by avg(score) desc 25、查询各科成绩前三名的记录考虑成绩并列情况 select s#,c# ,score from sc where score in ( select distinct top 3 score from sc group by c#,score ) order by score desc 26、查询每门课程被选修的学生数 ,数据库()() select c# as 课程号,count(c#)as 选修人数 from sc group by c# order by count(c#) desc 27、查询出只选修了一门课程的全部学生的学号和姓名 select sc.s#, from sc inner join student on student.s#=sc.s# group by sc.s#, having count(c#)=1 28、查询男生、女生人数 select ssex, count(*) as 总人数 from student group by ssex 29、查询姓“张”的学生名单 select sname from student where sname like '张%' 30、查询同名同性学生名单,并统计同名人数 select ssex,count(*) from student group by ssex 31、同年出生的学生名单(注:Student表中Sage列的类型是datetime) 32、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列 select c#,avg(score)平均成绩 from sc group by c# order by avg(score) asc 33、查询平均成绩大于的所有学生的学号、姓名和平均成绩 select top 1 student.s#,,avg(score)平均成绩 from student inner join sc on student.s#=sc.s# group by student.s#, order by avg(score) desc 34、查询课程名称为“数据库”,且分数低于80的学生姓名和分数 select , from sc,student,course where student.s#=sc.s# and sc.c#=course.c# and ='计算机基础' and <80 group by , 35、查询所有学生的选课情况; select student.s#,sname,c# from student left join sc on student.s#=sc.s# 36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数; select ,, from student,sc,course where student.s#=sc.s# and sc.c#=course.c# and >70 order by score desc 37、查询不及格的课程,并按课程号从大到小排列 select c#,score from sc where score<60 order by c# 38、查询课程编号为0001且课程成绩在70分以上的学生的学号和姓名; select student.s#,sname from sc,student where c#='0001' and score>70 and student.s#=sc.s# 39、求选了课程的学生人数 select count(s#)人数 from sc where <>0 40、查询选修“oracle”课程的学生中,成绩最高的学生姓名及其成绩 select top 1 ,max()成绩最高 from student inner join sc on student.s#=sc.s# inner join course on sc.c#=course.c# where ='oracle' group by order by max() desc 41、查询各个课程及相应的选修人数 select ,count(sc.c#) as 选修人数 from sc inner join course on sc.c#=course.c# group by order by count(sc.c#) desc, asc 42、查询不同课程成绩相同的学生的学号、课程号、学生成绩 43、查询每门功成绩最好的前两名 SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数 FROM SC t1 WHERE score IN (SELECT TOP 2 score FROM SC WHERE t1.C#= C# ORDER BY score DESC ) ORDER BY t1.C# 44、统计每门课程的学生选修人数(超过人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列 45、检索至少选修两门课程的学生学号 select s#, count(s#) as 选修课程数 from sc group by s# having count(s#)>1 46、查询全部学生都选修的课程的课程号和课程名 select c#,cname from course where c# in(select c# from sc) 47、查询没学过“叶平”老师讲授的任一门课程的学生姓名 select Sname from Student where S# not in ( select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='朱玉文') 48、查询两门以上不及格课程的同学的学号及其平均成绩 49、检索“”课程分数小于,按分数降序排列的同学学号 select s#,score from sc where score<60 order by score desc 50、删除“1005”同学的“0004”课程的成绩 delete from sc where s#='1005' and c#='0004'
2023年6月21日发(作者:)
SQL练习题库
表结构
Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表
试题:
1、查询“0001”课程比“C002”课程成绩高的所有学生的学号;
Select s# from sc
Where c#='0001' and score>any(select score from sc c#='0002')
2、查询平均成绩大于60分的同学的学号和平均成绩;
select s#,avg(score) from SC
group by s#
having avg(score)>60
3、查询所有同学的学号、姓名、选课数、总成绩;
select student.s#,,count(sc.c#)as 选课数,sum(score)总成绩 from student,sc
where student.s#=sc.s#
group by student.s#,
4、查询姓“张”的老师的个数;
select count(*)人数 from teacher
where tname like'张%'
5、查询没学过“叶平”老师课的同学的学号、姓名;
select student.s#, from student,course,teacher,sc
where student.s#=sc.s# and course.t#=teacher.t# and teacher.t# not in(select t# from teacher where tname='张丽芬')
group by student.s#,
6、查询学过“0001”并且也学过编号“0002”课程的同学的学号、姓名;
select sc.s#,sname from sc,student
where sc.c# = '0001' and student.s# = sc.s# and sc.s# in (select s# from sc where sc.c# = '0002')
--并(两表值)
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0001'
union
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0002'
--交(有相同值)
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0001'
intersect
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0002'
--差(不同值)
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0001'
except
select student.s#, from student,sc
where student.s#=sc.s# and sc.c#='0002'
7、查询学过“叶平”老师所教的所有课的同学的学号、姓名; select student.s#, from student,course,teacher,sc
where student.s#=sc.s# and course.t#=teacher.t# and teacher.t# in(select t# from teacher where tname='张丽芬')
group by student.s#,
8、查询课程编号“001”的成绩比课程编号“002”课程低的所有同学的学号、姓名;
select student.s#,sname,score from student,sc
where student.s#=sc.s# and score in(( select score from sc where c#='0001' ) 9、查询所有课程成绩小于60分的同学的学号、姓名; select student.s#,sname from student where s# in( select s# from sc where score<60) 10、查询没有学全所有课的同学的学号、姓名; select student.s#, from student,sc where student.s#=sc.s# group by student.s#, having count(c#)<(select count(c#) from course) 11、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名; select student.s#, from student,sc where student.s#=sc.s# and c#=any( select c# from sc where s#='1001' ) group by student.s#, 12、查询至少学过学号为“0001”同学所有一门课的其他同学学号和姓名; Select sc.s#,sname from sc inner join student on sc.s#=student.s# Where c# in (select c# from sc where s#=’0001’) 13、把“SC”表中“赵雁南”老师教的课的成绩都更改为此课程的平均成绩; update sc set score=(select avg() from sc,teacher,course where sc.c#=course.c# and course.t#=teacher.t# and ='赵雁南') where sc.c#=(select c# from course,teacher where course.t#=teacher.t# and tname='赵雁南' ) 14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名; select student.s#,sname from student,sc where student.s#=sc.s# and sc.c#=all(select c# from sc where s#='1005') and student.s#<>'1005' 15、删除学习“朱玉文”老师课的SC表记录; delete from sc where c# in(select c# from sc where c# in (select c# from course,teacher where teacher.t#=course.t# and ='朱玉文' ) ) 16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“0002”课程的同学学号、号课的平均成绩; insert into sc values select s# from sc where s# not in (select s# from sc where c#='0002' select avg(score) as 平均成绩 from sc where c#='0002' 17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示:学生ID,,数据库,企业管理,英语,有效课程数,有效平均分 select sc.s#,,,avg(score)as 平均成绩 from sc inner join course on sc.c#=course.c# where sc.c# in(select c# from course where cname=any(select cname from course where cname in('计算机基础','Oracle','软件工程'))) group by sc.s#,, order by avg(score) desc SELECT S# as 学生ID ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='0001') AS 计算机基础 ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='0002') AS Oracle ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='0011') AS 软件工程 ,COUNT(*) AS 有效课程数, AVG() AS 平均成绩 FROM sc AS t GROUP BY S# ORDER BY avg() desc 18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分 select c# 课程ID,max(score) 最高分,min(score) 最低分 from sc group by c# 19、按各科平均成绩从低到高和及格率的百分数从高到低顺序 select c#, avg(score) from sc where score>60 group by c# 20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(),马克思(),OO&UML 21、查询不同老师所教不同课程平均分从高到低显示 select course.t#,avg() as 平均分 from sc,course where sc.c#=course.c# group by course.t# order by avg() desc 22、查询如下课程成绩第3 名到第6 名的学生成绩单:企业管理,马克思,UML,数据库 [学生ID],[学生姓名],企业管理,马克思,UML,数据库,平均成绩 select student.s#,,, from student inner join sc on student.s#=sc.s# inner join course on sc.c#=course.c# where in('oracle','电路分析','计算机基础') order by , desc 23、统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60] select sc.c#,,count(*)人数 from sc,course where course.c#=sc.c# group by sc.c#, 24、查询学生平均成绩及其名次 select sc.s#,avg(score) from sc group by sc.s# order by avg(score) desc 25、查询各科成绩前三名的记录考虑成绩并列情况 select s#,c# ,score from sc where score in ( select distinct top 3 score from sc group by c#,score ) order by score desc 26、查询每门课程被选修的学生数 ,数据库()() select c# as 课程号,count(c#)as 选修人数 from sc group by c# order by count(c#) desc 27、查询出只选修了一门课程的全部学生的学号和姓名 select sc.s#, from sc inner join student on student.s#=sc.s# group by sc.s#, having count(c#)=1 28、查询男生、女生人数 select ssex, count(*) as 总人数 from student group by ssex 29、查询姓“张”的学生名单 select sname from student where sname like '张%' 30、查询同名同性学生名单,并统计同名人数 select ssex,count(*) from student group by ssex 31、同年出生的学生名单(注:Student表中Sage列的类型是datetime) 32、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列 select c#,avg(score)平均成绩 from sc group by c# order by avg(score) asc 33、查询平均成绩大于的所有学生的学号、姓名和平均成绩 select top 1 student.s#,,avg(score)平均成绩 from student inner join sc on student.s#=sc.s# group by student.s#, order by avg(score) desc 34、查询课程名称为“数据库”,且分数低于80的学生姓名和分数 select , from sc,student,course where student.s#=sc.s# and sc.c#=course.c# and ='计算机基础' and <80 group by , 35、查询所有学生的选课情况; select student.s#,sname,c# from student left join sc on student.s#=sc.s# 36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数; select ,, from student,sc,course where student.s#=sc.s# and sc.c#=course.c# and >70 order by score desc 37、查询不及格的课程,并按课程号从大到小排列 select c#,score from sc where score<60 order by c# 38、查询课程编号为0001且课程成绩在70分以上的学生的学号和姓名; select student.s#,sname from sc,student where c#='0001' and score>70 and student.s#=sc.s# 39、求选了课程的学生人数 select count(s#)人数 from sc where <>0 40、查询选修“oracle”课程的学生中,成绩最高的学生姓名及其成绩 select top 1 ,max()成绩最高 from student inner join sc on student.s#=sc.s# inner join course on sc.c#=course.c# where ='oracle' group by order by max() desc 41、查询各个课程及相应的选修人数 select ,count(sc.c#) as 选修人数 from sc inner join course on sc.c#=course.c# group by order by count(sc.c#) desc, asc 42、查询不同课程成绩相同的学生的学号、课程号、学生成绩 43、查询每门功成绩最好的前两名 SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数 FROM SC t1 WHERE score IN (SELECT TOP 2 score FROM SC WHERE t1.C#= C# ORDER BY score DESC ) ORDER BY t1.C# 44、统计每门课程的学生选修人数(超过人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列 45、检索至少选修两门课程的学生学号 select s#, count(s#) as 选修课程数 from sc group by s# having count(s#)>1 46、查询全部学生都选修的课程的课程号和课程名 select c#,cname from course where c# in(select c# from sc) 47、查询没学过“叶平”老师讲授的任一门课程的学生姓名 select Sname from Student where S# not in ( select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='朱玉文') 48、查询两门以上不及格课程的同学的学号及其平均成绩 49、检索“”课程分数小于,按分数降序排列的同学学号 select s#,score from sc where score<60 order by score desc 50、删除“1005”同学的“0004”课程的成绩 delete from sc where s#='1005' and c#='0004'
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