我想知道我是否可以使用解构来附加到列表中？
例如
p = []; q = []; var obj_1 = {a: 42, b: 52}; var obj_2 = {a: 43, b: 53}; var {p, q} = obj_1; {p, q} = obj_2;第一次应该给我：p = [42] q = [52]
然后下一次
应该给我p = [42,43] q = [52,53]
以上示例不起作用。 所以我的问题是是否可以通过破坏来实现。 或者，如果有一些替代方式？
I wonder if I somehow can use destructuring to to append into a list?
E.g.
p = []; q = []; var obj_1 = {a: 42, b: 52}; var obj_2 = {a: 43, b: 53}; var {p, q} = obj_1; {p, q} = obj_2;First time it should give me: p = [ 42 ] q = [ 52 ]
and then next time
should give me p = [ 42, 43 ] q = [ 52, 53 ]
Above example doesn't work. So my question is whether it is possible to do so with destructing. Or if there are some alternative way?
最满意答案
不是那种有用或省力的方式。 你可以这样做：
({a:p[p.length], b:q[q.length]} = obj_1);......但...... :-)
const p = [];
const q = [];
const obj_1 = {a: 42, b: 52};
const obj_2 = {a: 43, b: 53};
({a:p[p.length], b:q[q.length]} = obj_1);
console.log("p", JSON.stringify(p), "q", JSON.stringify(q));
({a:p[p.length], b:q[q.length]} = obj_2);
console.log("p", JSON.stringify(p), "q", JSON.stringify(q));
Not in a way that's all that useful or effort-saving. You can do this:
({a:p[p.length], b:q[q.length]} = obj_1);
...but... :-)
const p = [];
const q = [];
const obj_1 = {a: 42, b: 52};
const obj_2 = {a: 43, b: 53};
({a:p[p.length], b:q[q.length]} = obj_1);
console.log("p", JSON.stringify(p), "q", JSON.stringify(q));
({a:p[p.length], b:q[q.length]} = obj_2);
console.log("p", JSON.stringify(p), "q", JSON.stringify(q));
是否有可能使用解构来追加？(Is it possible to use destructuring to append?)
我想知道我是否可以使用解构来附加到列表中？
例如
p = [];
q = [];
var obj_1 = {a: 42, b: 52};
var obj_2 = {a: 43, b: 53};
var {p, q} = obj_1;
{p, q} = obj_2;
第一次应该给我：p = [42] q = [52]
然后下一次
应该给我p = [42,43] q = [52,53]
以上示例不起作用。 所以我的问题是是否可以通过破坏来实现。 或者，如果有一些替代方式？
I wonder if I somehow can use destructuring to to append into a list?
E.g.
p = [];
q = [];
var obj_1 = {a: 42, b: 52};
var obj_2 = {a: 43, b: 53};
var {p, q} = obj_1;
{p, q} = obj_2;
First time it should give me: p = [ 42 ] q = [ 52 ]
and then next time
should give me p = [ 42, 43 ] q = [ 52, 53 ]
Above example doesn't work. So my question is whether it is possible to do so with destructing. Or if there are some alternative way?
最满意答案
不是那种有用或省力的方式。 你可以这样做：
({a:p[p.length], b:q[q.length]} = obj_1);
......但...... :-)
const p = [];
const q = [];
const obj_1 = {a: 42, b: 52};
const obj_2 = {a: 43, b: 53};
({a:p[p.length], b:q[q.length]} = obj_1);
console.log("p", JSON.stringify(p), "q", JSON.stringify(q));
({a:p[p.length], b:q[q.length]} = obj_2);
console.log("p", JSON.stringify(p), "q", JSON.stringify(q));
Not in a way that's all that useful or effort-saving. You can do this:
({a:p[p.length], b:q[q.length]} = obj_1);
...but... :-)
const p = [];
const q = [];
const obj_1 = {a: 42, b: 52};
const obj_2 = {a: 43, b: 53};
({a:p[p.length], b:q[q.length]} = obj_1);
console.log("p", JSON.stringify(p), "q", JSON.stringify(q));
({a:p[p.length], b:q[q.length]} = obj_2);
console.log("p", JSON.stringify(p), "q", JSON.stringify(q));
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