通过列表作为值迭代python字典(Iterating through a python dictionary with lists as values)

我正在尝试迭代看起来像这样的字典：

d = { "list_one": [ "hello", "two", "three" ], "list_two": [ "morning", "rain" ] }

我正在使用这个功能：

def combine_words(d): for k, v in d.items(): a = {k: ("|".join(v))} return a

当我用print运行它时，我的输出只是一个键，值对。 我不确定这里发生了什么。 我的理想出局是：

{ 'list_one': 'hello|two|three', 'list_two': 'morning|rain' }

I'm trying to iterate through a dictionary that looks like:

d = { "list_one": [ "hello", "two", "three" ], "list_two": [ "morning", "rain" ] }

I'm using the function:

def combine_words(d): for k, v in d.items(): a = {k: ("|".join(v))} return a

When I run this with print, my output is just one key, value pair. I'm not sure what is happening here. My ideal out put would be:

{ 'list_one': 'hello|two|three', 'list_two': 'morning|rain' }

最满意答案

每次循环都会被一个新的dict取代。 你想要一个词典理解。

def combine_words(d): return {k: "|".join(v) for k, v in d.items()}

a gets replaced by a new dict each time through your loop. You want a dict comprehension.

def combine_words(d): return {k: "|".join(v) for k, v in d.items()}通过列表作为值迭代python字典(Iterating through a python dictionary with lists as values)

我正在尝试迭代看起来像这样的字典：

d = { "list_one": [ "hello", "two", "three" ], "list_two": [ "morning", "rain" ] }

我正在使用这个功能：

def combine_words(d): for k, v in d.items(): a = {k: ("|".join(v))} return a

当我用print运行它时，我的输出只是一个键，值对。 我不确定这里发生了什么。 我的理想出局是：

{ 'list_one': 'hello|two|three', 'list_two': 'morning|rain' }

I'm trying to iterate through a dictionary that looks like:

d = { "list_one": [ "hello", "two", "three" ], "list_two": [ "morning", "rain" ] }

I'm using the function:

def combine_words(d): for k, v in d.items(): a = {k: ("|".join(v))} return a

When I run this with print, my output is just one key, value pair. I'm not sure what is happening here. My ideal out put would be:

{ 'list_one': 'hello|two|three', 'list_two': 'morning|rain' }

最满意答案

每次循环都会被一个新的dict取代。 你想要一个词典理解。

def combine_words(d): return {k: "|".join(v) for k, v in d.items()}

a gets replaced by a new dict each time through your loop. You want a dict comprehension.

def combine_words(d): return {k: "|".join(v) for k, v in d.items()}